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Los Angeles Lakers 1988 Championship - The Playoffs

The 1988 NBA Playoffs: Los Angeles Lakers and all the other teams

Here you have the information about the 1988 NBA Playoffs and the path the Los Angeles Lakers took to win a new championship. The league had 23 teams in 1988 and the best 16 (8 from each Conference) competed in a traditional playoff format.

Western Conference NBA Finals Eastern Conference
(1) Lakers 3 3 Celtics (1)
Lakers 4 4 Boston
(8) Spurs 0 1 Knicks (8)
Lakers 4 2 Boston
(4) Blazers 1 3 Hawks (4)
Jazz 3 3 Hawks
(5) Jazz 3 Lakers 4 2 Bucks (5)
L.A. Lakers
Champion
(2) Nuggets 3 Pistons 3 3 Pistons (2)
Nuggets 2 4 Pistons
(7) Sonics 2 2 Bullets (7)
Mavs 3 4 Pistons
(3) Mavs 3 3 Bulls (3)
Mavs 4 1 Bulls
(6) Rockets 1 2 Cavaliers (6)

Western Conference teams:

Lakers = Los Angeles Lakers
Spurs = San Antonio Spurs
Blazers = Portland Trail Blazers
Jazz = Utah Jazz
Nuggets = Denver Nuggets
Sonics = Seattle Supersonics
Mavs = Dallas Mavericks
Rockets = Houston Rockets

Eastern Conference teams:

Celtics = Boston Celtics
Knicks = New York Knicks
Hawks = Atlanta Hawks
Bucks = Milwaukee Bucks
Pistons = Detroit Pistons
Bullets = Washington Bullets
Bulls = Chicago Bulls
Cavaliers = Cleveland Cavaliers

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